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Sharing of electrons...bonding of compounds.....?

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Sharing of electrons...bonding of compounds.....?

Post  humblemetsuke on Thu Feb 26, 2015 12:44 pm

Hi guys, really stuck with my chemistry work....

I am asked:

Atoms of nitrogen and element X form a bond in which the electrons are shared equally; element X could be
Carbon
Oxygen
Chlorine
Phosphorus?

I am told the answer is chlorine but I do not understand why. Nitrogen is 2,5. Chlorine is 2, 8,, 7 so I thought that meant that Nitrogen needs to lose three electrons; to give it a positive charge; and chlorine would gain 3 electrons. But then, that would give us 2,8 for Nitrogen and 2,8, 8 2 for the chloride....

So I am now totally confused

humblemetsuke

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SHARING OF ELECTRONS...BONDING OF COMPOUNDS.....?

Post  DrPelezo on Sun May 17, 2015 3:35 am

Case IV:  N/P
Valence Number = N + P = 5 + 5 = 10
Octet Number = N + P = 8 + 8 = 16
Bond No =[(O – V)/] = (16 – 10)/2 = 6/2 = 3 covalent bonds
Free Pr e- on N  = V – S / 2 = 10 – 8 /2 = 2/2 = 1 on N
Free Pr e- on P  = V – S / 2 = 10 – 8 /2 = 2/2 = 1 on P
The structure conforming to octet rule whose elements  have lowest electronegativity is the Nitrogen/Phosphorous structure.
Lewis Structure:  :N Ξ P:

The N/Cl structure is not allowed as the Bond Number is 2.5 (not allowed) must be whole number.

DrPelezo

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