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A buffer question

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A buffer question

Post  Tara on Mon Sep 05, 2011 5:53 am

For example we've got a buffer solution below:
HA <-------> H^+ + A^-
NaA -------> Na^+ + A^-
By adding NaOH (Na^+ and OH^-) to the solution , OH^- would react with H^+ and H^+ decreases. so the equilibrium turns right to increase [H^+] again . so [H^+] doesn't change much.That's our buffer solution.
The question is what is the role of our salt HERE ?

Please explain the role of NaA in MY example. I know the roll of salt when you add an acid. But i don't know NaA's role when adding a base (OH^-)

I used to know the answer but i can't remember it... ... something about Ka ...


Thanks.

Tara

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Re: A buffer question

Post  charco on Tue Sep 13, 2011 5:02 pm

Tara wrote:For example we've got a buffer solution below:
HA <-------> H^+ + A^-
NaA -------> Na^+ + A^-
By adding NaOH (Na^+ and OH^-) to the solution , OH^- would react with H^+ and H^+ decreases. so the equilibrium turns right to increase [H^+] again . so [H^+] doesn't change much.That's our buffer solution.
The question is what is the role of our salt HERE ?

Please explain the role of NaA in MY example. I know the roll of salt when you add an acid. But i don't know NaA's role when adding a base (OH^-)

I used to know the answer but i can't remember it... ... something about Ka ...


Thanks.

The salt provides a large reservoir of negative A- ions that can 'mop up' any H+ ions that are added. They do not specifically have any role when base is added. (that's what the HA is for)

charco

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